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📚专栏地址：PAT题解集合
📝原题地址：题目详情 - 1132 Cut Integer (pintia.cn)
🔑中文翻译：切整数
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1132 Cut Integer

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <2³¹). It is guaranteed that the number of digits of Z is an even number.

Output Specification:

For each case, print a single line Yes if it is such a number, or No if not.

Sample Input:

3
167334
2333
12345678

Sample Output:

Yes
No
No

题意

给定一个数 N ，它可以切分成两个整数 a 和 b ，其中 a 是等于 N 的前半部分而 b 是后半部分，例如 167334 划分成 a=167 和 b=334 。

我们需要判断 N 是否可以整除 a*b 。

思路

具体思路如下：

1. 输入整数 num ，并计算其长度。
2. 根据长度划分成左右两半整数 a 和 b 。
3. 根据 num 是否能整除 a*b 输出对应结果。

代码

#include
using namespace std;int main()
{int T;cin >> T;while (T--){string num;cin >> num;//切分整数int len = num.size();int a = stoi(num.substr(0, len / 2));int b = stoi(num.substr(len / 2));int n = stoi(num);if (a * b && n % (a * b) == 0)    puts("Yes");else    puts("No");}return 0;
}