

SELECT customer_number
FROM Orders
GROUP BY customer_number
having count(order_number)=(SELECT max(o1.number)FROM (SELECT count(order_number) numberFROM OrdersGROUP BY customer_number) o1
)



SELECT player_id,min(event_date) first_login
FROM Activity
GROUP BY player_id;



# ①先筛选出2020年的所有用户②再去分组筛选出来
select L1.user_id,MAX(L1.time_stamp) last_stamp
FROM
(SELECT *FROM LoginsWHERE DATE_FORMAT(time_stamp,"%Y")=2020
) L1
GROUP BY L1.user_id;



SELECT e1.event_day day,e1.emp_id emp_id,sum(e1.differ_value) total_time
FROM
(SELECT emp_id,event_day,out_time-in_time differ_valueFROM Employees
) e1
GROUP BY e1.emp_id,e1.event_day;

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